LinkedIn Tango #601 Answer & Analysis

Use the Cross clue between R1C1 and R1C2 (cell0 rightEdge Cross). Because of surrounding givens and balance constraints in row 1 and column 1/2, one of the two must be Sun and the other Moon. Choosing the placement consistent with the final solution becomes a forcing choice as you propagate the consequences.

R4C1 and R4C2 (cells 18 and 19) are linked by an Equal clue. Consider the row balance for R4: since neighboring cells and column constraints demand enough Suns in that row, the Equal pair must be the same symbol that helps reach 3 Suns for that row. In the solved layout those two are Suns, which then reduces freedom in columns 1 and 2.

After placing the Equal pair as Suns, check rows and columns next to long runs. If placing another Sun would create three Suns in a row in any row or column, that cell must be Moon. Use this repeatedly to fill cells that otherwise look ambiguous.

With several Suns fixed (including the bottom-right given Suns), count Suns/Moons in each column. If a column already has two Suns, any remaining cells in that column that would otherwise become Sun must instead be Moon to keep the 3/3 balance. Repeat this until each column’s three-of-each requirement is satisfied.

Use the Cross clues (for example the Cross linking R4C4 and R5C4) and the no-three rule to finish any remaining cells. After filling by propagation, verify row and column balances and that every Equal/Cross edge is satisfied.