LinkedIn Tango #591 Answer & Analysis

There is a Cross between R1C1 and R2C1 (edge between cell0 and cell6). Using column balance and the other givens in column 1 later in the solution, R1C1 must be a Sun to satisfy the overall distribution without creating an impossible three-in-a-row elsewhere. This placement is consistent with the final solution and follows from combining the Cross clue with row/column balancing logic.

R1C5 and R2C5 are linked by an Equal edge (cell4 bottom Equal, cell10 top Equal). If one becomes Moon due to row constraints, the other must match. Use the given Suns in row 1 (R1C2 and R1C4) and the requirement of 3 Suns per row to deduce that R1C5 and R2C5 are Moons in the final configuration.

The given Moon at R2C2 and nearby Suns in the same column help restrict options for R3C2 and R4C2. Combine the no-three rule horizontally and the column balance to fix R2C1 as Moon (opposite R1C1) and to force specific placements in R2 and R3 that follow in the solved board.

There are multiple Equal or Cross clues connecting rows 5 and 6 (for example: R5C1–R6C1 Equal, R5C5–R6C5 Equal, plus some Cross edges nearby). These pairs force matching/opposite symbols in the last two rows; combine that with the partial fills from earlier steps to complete rows 5 and 6.

After propagating the above constraints, fill the remaining cells so every row and column has three Suns and three Moons and no three identical symbols appear consecutively. The final board satisfies all Equal and Cross clues and the row/column balance. Use each edge clue as a final consistency check.