LinkedIn Tango #587 Answer & Analysis

Use the given Moon at R1C2 and the column/row balance to determine a forced symbol at the corner. On this board the combination of the R1 balance target (3 Suns / 3 Moons) and column constraints makes R1C1 a Sun.

Focus on the cluster around R1C5–R1C6 and R2C5–R2C6. Start with the Equal links: R1C5 = R1C6 and R1C5 = R2C5 force those three to share the same symbol. The Cross relationships from those cells to R2C6 / R2C6’s neighbors force the opposite symbol there. That small chain fixes R1C5/R1C6 as Moon and R2C6 as Sun in the final solution, which then helps balance rows 1 and 2.

Examine R5C1 (cell 24), R5C2 (cell 25), R6C1 (cell 30) and R6C2 (cell 31). There are Equal and Cross edges linking these four cells into a mini-network (R5C1 = R6C1 and R5C1 × R5C2, R5C2 × R6C2, R6C1 = R6C2). That network forces R5C1 = Moon, R6C1 = Moon, and R5C2 = Sun (so R6C2 becomes Moon in the consistent final layout).

With those clusters fixed, apply the 3/3 rule and the no-three rule to each remaining row and column. For example, once some Suns and Moons are placed in rows 1, 2 and 5, the remaining cells in rows 3 and 4 must be filled to reach 3 Suns/3 Moons while avoiding three identical symbols in a row — this forces several middle placements and removes mirror alternatives.

Finish by checking each column also has 3 Suns and 3 Moons and make any final single-cell deductions. The remaining cells become forced by the combination of parity (3/3), no-three-in-a-row, and satisfied Equal/Cross chains. Then run a final verification against all clues.