LinkedIn Tango #616 Answer & Analysis

Row 4 already has Suns at R4C3 and R4C4, so R4C5 must be Moon to avoid three Suns in a row. The Cross clue between R4C5 and R5C5 then forces R5C5 to be Sun.

Column 2 contains the Equal pairs R2C2 = R3C2 and R4C2 = R5C2. Since row 4 already has Suns at R4C3 and R4C4, R4C2 cannot be Sun or row 4 would contain three Suns in a row. That means R4C2 and R5C2 must be Moons, and to keep column 2 balanced, R2C2 and R3C2 must be Suns.

Now row 3 has Suns at R3C2 and R3C3, so R3C1 must be Moon to avoid three Suns in a row. In row 5, the Equal clue gives R5C3 = R5C2, so R5C3 is also Moon. Then the Cross clue at R5C4 makes R5C4 the opposite value, which is Sun.

Row 2 has a Cross chain: R2C3 is opposite R2C4, and R2C5 is also opposite R2C4. The column balance in column 4 works only if R2C4 is Sun, which forces R2C3 and R2C5 to be Moons. Then the Cross clue between R2C5 and R3C5 gives R3C5 a Sun.

With rows 2 through 5 settled, each column has enough information to finish rows 1 and 6. The remaining cells are forced by the requirement that every column must end with exactly 3 Suns and 3 Moons, while also avoiding any run of three identical symbols. That gives the final completed grid and matches today's Tango solution.