LinkedIn Tango #585 Answer & Analysis

There are nine given symbols: R2 has Moon, Moon, Sun (R2C1–R2C3); R4 has Moon, Sun, Moon (R4C1–R4C3); R6 has Sun, Sun, Moon (R6C1–R6C3). Use these to count how many Suns and Moons remain in their rows and columns.

R1C1–R1C3 form a constrained unit: Cross at R1C1–R1C2 forces R1C2 opposite R1C1; Equal at R1C2–R1C3 forces R1C3 same as R1C2. With R1C1 = Moon this yields R1C2 = Sun and R1C3 = Sun, satisfying both the edge clues and helping row1 reach its 3S/3M target.

Cells at indices 12–14 carry a Cross edge between 12–13 and an Equal between 13–14: that forces 12 opposite 13 and 13 equal 14. In the completed grid that becomes Sun, Moon, Moon (R3C1–R3C3). Once this local pattern is set, use the row balance and no-three rule to place the remaining cells in row 3 (R3C4–R3C6).

Row 5 has a Cross chain across R5C1–R5C3 (cells 24–26): the clues force alternating symbols there (Sun, Moon, Sun). Those placements, plus the no-three rule and column balances from the givens above and below, quickly determine R5C4–R5C6.

After propagating those chains, the remaining empty cells are resolved by simple row/column balance and no-three-in-a-row elimination. Check each column and row has three Suns and three Moons and that all Cross/Equal edges are satisfied to confirm the solution.