LinkedIn Tango #582 Answer & Analysis

Start with the equal link between R1C1 and R2C1 (cell0 bottomEdge = Equal / cell6 topEdge = Equal). Because these two must match and later balance checks make Sun the consistent assignment here, place R1C1 = Sun and R2C1 = Sun. This anchors the left column and interacts with vertical Cross clues below.

R1C2—R1C3 is a Cross (cell1 rightEdge = Cross), so those two are opposite. Also R1C3—R1C4 is Equal (cell2 rightEdge = Equal / cell3 leftEdge = Equal). If you find R1C3 must be Sun by combining with nearby constraints, R1C2 becomes Moon and R1C4 also Sun. This resolves the top row pattern without breaking the no-three rule.

There is a Cross between R3C1 and R2C1 (cell12 topEdge = Cross). Since R2C1 was set Sun, R3C1 must be Moon. That then propagates downward because R3C1 and R4C1 may have further Cross/Equal constraints — continue marking opposites or equals as indicated.

In the lower-right area there is an Equal between R6C2–R6C3 (cell31 rightEdge = Equal) and a Cross chain linking R5C5↔R6C5↔R6C6 (cells around 29/35). Use the known R5C5 = Sun (given) to propagate R6C5 and R6C6 via Cross/Equal clues and then fill R6C2–R6C3 as a matching pair. These local closures resolve several rows/columns quickly.

Once most constrained blocks are filled, use the requirement that each row and column must have three Suns and three Moons and ensure no three identical symbols are adjacent. Remaining cells are forced by simple elimination combined with adjacent Equal/Cross clues.