LinkedIn Mini Sudoku #334 Answer & Analysis

Row 1 already has 1, 2, 3, and 4, so the missing digits are 5 and 6. The top-left box eliminates 5 from R1C1, so R1C1 = 6, and then R1C6 = 5. Column 2 also has only one missing digit, so R5C2 = 6. Column 5 is down to one missing digit as well, so R2C5 = 6.

With Row 1 fixed, the top-left box now leaves only 3 and 4 for R2C1 and R2C3. Column 3 can only take 4 there, so R2C3 = 4 and R2C1 = 3. In the top-right box, the remaining digits are 1 and 2, which forces R2C4 = 1 and R2C6 = 2.

The bottom-right box has 4, 5, 2, and 3 already placed, so it must contain 1 and 6 in R5C6 and R6C6. That makes Row 6 finish immediately, so R6C1 = 1. Then Column 1 leaves 2 and 3? Actually, after the earlier placements, Column 1 is reduced to 4 and 5 for the middle rows, which lets Row 5 finish as R5C1 = 2 and R5C3 = 3.

Column 1 now leaves 4 and 5 for R3C1 and R4C1. Column 3 leaves 6 and 1 for R3C3 and R4C3, and Row 3 must take 6 at R3C3. That pushes R4C3 to 1, Column 4 to 5 at R3C4 and 6 at R4C4, and the last cells become R3C6 = 3 and R4C6 = 4. The solved grid is: 6 1 2 3 4 5 3 5 4 1 6 2 4 2 6 5 1 3 5 3 1 6 2 4 2 6 3 4 5 1 1 4 5 2 3 6

Check the completed board one last time: every row contains 1 to 6 exactly once, every column contains 1 to 6 exactly once, and every 2x3 box contains 1 to 6 exactly once. That confirms the LinkedIn Mini Sudoku answer for #334.